Linked from

The 17 pages that link to Ernst Zermelo, each with the reason it gives.

• David HilbertRelated: Zermelo’s axioms offered a competing route to secure mathematical foundations.

• Set theoryRelated: His axiomatization addressed paradoxes and included the axiom of choice.

• Axiom of choiceRelated: His 1904 proof made the principle's role in set theory explicit.

• Well-ordering theoremRelated: His proof established the theorem using a principle that became the axiom of choice.

• Cumulative hierarchyRelated: His foundational work helped establish the framework in which staged set construction is studied.

• Zorn's lemmaRelated: Zorn's lemma belongs to the family of principles equivalent to Zermelo's axiom of choice.

• Axiom of extensionalityRelated: His axiomatization made extensionality part of a systematic foundation for set theory.

• Diagonal argumentRelated: Axiomatic set theory supplied a rigorous framework for interpreting diagonal constructions involving sets.

• Axiom of dependent choiceRelated: His work on the axiom of choice established the setting in which weaker choice principles were later studied.

• Löwenheim–Skolem theoremRelated: Debate about categorical axiomatizations of set theory helped frame the theorem's significance.

• Axiom of infinityRelated: His system included an axiom guaranteeing an infinite set.

• Axiom schema of specificationRelated: His 1908 axioms included the principle later called specification.

• Felix HausdorffRelated: Zermelo and Hausdorff worked within the foundational debates surrounding infinite sets.

• Well-orderRelated: His 1904 theorem established the claim that every set can be well-ordered, assuming choice.

• Axiom of Empty SetRelated: His axiomatization helped establish the framework in which the axiom is stated.

• Skolem's paradoxRelated: Skolem's analysis addressed the first-order axiomatic framework associated with Zermelo's set theory.

• Teichmüller–Tukey lemmaRelated: His work established foundational forms of the axiom of choice to which the lemma is equivalent.