Linked from

The 14 pages that link to Semiperimeter, each with the reason it gives.

• IncenterRelated: The inradius satisfies area equals semiperimeter times inradius.

• IncircleRelated: The incircle’s area equals the triangle’s area divided by this half-perimeter.

• Brahmagupta's formulaRelated: The formula combines the semiperimeter with each side length.

• Euler's inequalityRelated: The inradius-area identity uses the triangle's semiperimeter as a factor.

• Bretschneider's formulaRelated: The side-length factor uses the semiperimeter and its differences from each side.

• Weitzenböck's inequalityRelated: The factors s−a, s−b, and s−c in Heron's formula help prove the bound.

• Hadwiger–Finsler inequalityRelated: It appears in Heron’s formula, a standard route for proving the inequality.

• Pitot theoremRelated: For a tangential quadrilateral, each pair of opposite sides sums to the semiperimeter.

• Conway circle theoremRelated: The theorem’s contact distances can be expressed using the triangle’s semiperimeter.

• Equal Incircles TheoremRelated: A triangle’s inradius equals its area divided by its semiperimeter.

• Japanese theoremRelated: Triangle inradius equals area divided by semiperimeter, the key relation behind the equality.

• Japanese theorem for cyclic polygonsRelated: For a triangle, its area equals its inradius times its semiperimeter.

• Mollweide's formulaRelated: The side sums in one identity can be rewritten using the triangle's semiperimeter.